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IF y = y (x) is the solution of the diff...

IF y = y (x) is the solution of the differential equation, `x (dy)/(dx) = y (log_(e) y - log_(e) x + 1)`, when y(1) = 2, then y(2) is equal to _______

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To solve the differential equation \( x \frac{dy}{dx} = y (\log_e y - \log_e x + 1) \) with the initial condition \( y(1) = 2 \), we will follow these steps: ### Step 1: Rearranging the Equation We start with the given differential equation: \[ x \frac{dy}{dx} = y (\log_e y - \log_e x + 1) \] Rearranging gives: \[ \frac{dy}{dx} = \frac{y}{x} (\log_e y - \log_e x + 1) \] ### Step 2: Simplifying the Logarithmic Terms Using the property of logarithms, we can combine the logarithmic terms: \[ \log_e y - \log_e x + 1 = \log_e \left(\frac{y}{x}\right) + 1 \] Thus, we can rewrite the equation as: \[ \frac{dy}{dx} = \frac{y}{x} \left( \log_e \left(\frac{y}{x}\right) + 1 \right) \] ### Step 3: Substituting \( y = bx \) To solve this homogeneous differential equation, we can substitute \( y = bx \), where \( b \) is a function of \( x \). Therefore: \[ \frac{dy}{dx} = b + x \frac{db}{dx} \] Substituting into the equation gives: \[ b + x \frac{db}{dx} = b \left( \log_e b + 1 \right) \] ### Step 4: Rearranging the Equation Rearranging leads to: \[ x \frac{db}{dx} = b \log_e b \] This can be separated as: \[ \frac{db}{b \log_e b} = \frac{dx}{x} \] ### Step 5: Integrating Both Sides Integrating both sides: \[ \int \frac{db}{b \log_e b} = \int \frac{dx}{x} \] Let \( t = \log_e b \), then \( db = b dt \) and \( b = e^t \), so: \[ \int \frac{1}{t} dt = \int \frac{dx}{x} \] This gives: \[ \log_e |\log_e b| = \log_e |x| + C \] ### Step 6: Exponentiating Exponentiating both sides results in: \[ \log_e b = kx \] where \( k = e^C \). Thus: \[ b = e^{kx} \] ### Step 7: Substituting Back for \( y \) Recalling that \( y = bx \): \[ y = x e^{kx} \] ### Step 8: Using the Initial Condition Using the initial condition \( y(1) = 2 \): \[ 2 = 1 \cdot e^{k \cdot 1} \implies e^k = 2 \implies k = \log_e 2 \] Thus, the solution becomes: \[ y = x e^{(\log_e 2)x} = x \cdot 2^x \] ### Step 9: Finding \( y(2) \) Now we need to find \( y(2) \): \[ y(2) = 2 \cdot 2^2 = 2 \cdot 4 = 8 \] ### Final Answer Thus, \( y(2) \) is equal to: \[ \boxed{8} \] ---
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