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The area that is enclosed in the circle ...

The area that is enclosed in the circle `x^(2)+y^(2)=2` which is not common enclosed by `y=x & y^(2)-x` is

A

`1/3(12pi-1)`

B

`1/6(12pi-1)`

C

`1/3(6pi-1)`

D

`1/6(24pi-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
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[" The area that is enclosed in the "],[" circle "x^(2)+y^(2)=2" which is not "],[" common area enclosed by "],[y=x&y^(2)=x" is "],[[" (A) "(1)/(12)(2 pi-1)," (b) "],[" (B) "(1)/(6)(12 pi-1),(1)/(12)(6 pi-1)],[" (D) "(1)/(12)(12 pi-1)]]

Find the area enclosed by the circle x^(2)+y^(2)=a^(2)

Knowledge Check

  • Find area of the region enclosed by the circle x^(2) + y^(2) = 1 and which is not common to the region bounded by |x+ y| le 1 and | x - y | le 1

    A
    `pi - 1`
    B
    `pi- sqrt(2)`
    C
    `pi - 2`
    D
    `pi - sqrt(3)`

  • Find area of the region enclosed by the circle x^(2) + y^(2) = 1 and which is not common to the region bounded by |x + y| le 1 and x - y | le 1

    A
    `pi - 1`
    B
    `pi - sqrt(2)`
    C
    `pi - 2`
    D
    `pi - sqrt(3)`

  • What is the area enclosed by the curve 2x^(2)+y^(2)=1 ?

    A
    `2pi`
    B
    `pi`
    C
    `(pi)/2`
    D
    `(pi)/(sqrt(2))`

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