[" Lattice energy of "NaCl(s)" is "-790kJmol^(-1)" and enthalpy of hydration is "-785kJmol^(-1)" .Calculate enthalpy of solution of "],[NaCl(s)" ."]

Lattice energy of NaCl(s) is -790 kJ " mol"^(-1) and enthalpy of hydration is -785 kJ " mol"^(-1) . Calculate enthalpy of solution of NaCl(s).

Lattice energy of NaCl(s) is -790 kJ " mol"^(-1) and enthalpy of hydration is -785 kJ " mol"^(-1) . Calculate enthalpy of solution of NaCl(s).

Lattice energy of NaCl_((s)) is -788kJ mol^(-1) and enthalpy of hydration is -784kJ mol^(-1) . Calculate the heat of solution of NaCl_((s)) .

Lattice energy of NaCl_((s)) is -788kJ mol^(-1) and enthalpy of hydration is -784kJ mol^(-1) . Calculate the heat of solution of NaCl_((s)) .

The lattice enthalpy of solid NaCl is 772 kJ mol^(-1) and enthalpy of solution is 2 kJmol^(-1) . If the hydration enthaply of Na^(+) & Cl^(-) ions are in the ratio of 3 : 2.5 , what is the enthalpy of hydration of chloride ion ?

The enthalpy of solution of sodium chloride is 4 kJ mol^(-1) and its enthalpy of hydration of ion is -784 kJ mol^(-1) . Then the lattice enthalpy of NaCl (in kJ mol^(-1) ) is