[f(x)=cos^(2)theta cos^(2)thetaquad x],[xquad sin^(2)theta cos^(2)theta|,theta in(0,pi/2)" then roots "],[f(x)=0" are "],[1/2,-1]

If f(x)=|{:( sin^2 theta , cos^(2) theta , x),(cos^(2) theta , x , sin^(2) theta ),( x , sin^(2) theta , cos^2 theta ):}|, theta in (0,pi//2), then roots of f(x)=0 are

If f(x)=|{:( sin^2 theta , cos^(2) theta , x),(cos^(2) theta , x , sin^(2) theta ),( x , sin^(2) theta , cos^2 theta ):}| theta in (0,pi//2), then roots of f(x)=0 are

If f(x)=|{:( sin^2 theta , cos^(2) theta , x),(cos^(2) theta , x , sin^(2) theta ),( x , sin^(2) theta , cos^2 theta ):}| theta in (0,pi//2), then roots of f(x)=0 are

If f(x)=|{:( sin^2 theta , cos^(2) theta , x),(cos^(2) theta , x , sin^(2) theta ),( x , sin^(2) theta , cos^2 theta ):}| theta in (0,pi//2), then roots of f(x)=0 are

If f(x)=|{:( sin^2 theta , cos^(2) theta , x),(cos^(2) theta , x , sin^(2) theta ),( x , sin^(2) theta , cos^2 theta ):}| theta in (0,pi//2), then roots of f(x)=0 are

If (cos theta+cos2 theta)+sin2 theta(1+2cos theta)=2sin theta,theta in[-pi,pi] then

Range of f(theta)=cos^(2)theta(cos^(2)theta+1)+2sin^(2)theta is

If |{:(1+cos^(2)theta,sin^(2)theta,4cos6theta),(cos^(2)theta,1+sin^(2)theta,4cos6theta),(cos^(2)theta,sin^(2)theta,1+4cos6theta):}|=0 , and theta in (0,(pi)/(2)) , then value of theta is

cos^(2)theta-sin theta.cos theta-(1)/(2)=0