The series of natural numbers is divided into groups asfollows ;`(1), (2,3), (4,5,6), (7,8,9,10)` and so on. Find the sum of the numbers in the `n^th` group is

The series of natural number is divided into groups as follows , (1), (2,3),(4,5,6),(7,8,9,10) and so on. Find the sum of the number in the nth group is

Natural numbers are divided into groups in the following way: 1,(2,3),(4,5,6),(7,8,9,10), Show that the sum of the numbers in the nth group is (n(n^2+1))/2

The series of natural numbers is divided into groups :(1);(2,3,4);(5,6,7,8,9)... and so on. The sum of numbers in the n^(th) group is

The series of natural numbers is divided into groups :(1);(2,3,4);(5,6,7,8,9)... and so on. The sum of numbers in the n^(th) group is

The series of natural numbers is divided into groups :(1);(2,3,4);(5,6,7,8,9)... and so on. The sum of numbers in the n^(th) group is

The series of natural numbers is divided into groups: (1);(2,3,4);(5,6,7,8,9)... and so on.The sum of numbers in the n^(th) group is

The series of natural numbers is divided into grounds as (1), (2, 3, 4), (3, 4, 5, 6, 7), (4, 5, 6, 7, 8, 9, 10)………. If sum of elements in the 20^(th) ground is l , then l is equal to