Twoelectrodes are fitted in conductance cell 1.5 cm apart while the area of cross-section of each electrode is `0.75 cm^(2)`. The cell constant is

Two electrodes are fitted in conductance cell 1.5 cm apart while the area of cross-section of each electrode is 0.75 cm^(2) . The cell constant is

The two platinum electrodes fitted in a conductance cell are 1.5 cm apart while the cross sectional area of each electrode is 0.75 cm^(2) . The cell constant is :

The two Pt electrodes fitted in a conductance cell are 1.5 cm apart while the cross - sectional area of each electrode is 0.75cm . What is the cell constant?

The two Pt electrodes fitted in a conductance cell are 1.5 cm apart while the cross - sectional area of each electrode is 0.75cm . What is the cell constant?

The two Pt electrodes fitted in a conductance cell are 1.5 cm apart while the cross - sectional area of each electrode is 0.75cm . What is the cell constant?

A conductivity cell dipped in 0.0005 M NaCl gives at 25^@C resistance of 13710 ohms.If the electrode of the conductivity cell are 0.7 cm apart and the area of cross section of the electrode is 0.82cm^2 ,what is the molar conductivity of the solution at 25^@C ?

The distance between the electrodes of a conductivity cell is 0.98 cm and area of cross section of theeletrodeis 1.3cm^2 . Calculate the cell constant for the cell.

Distance between the electrodes of a conductivity cell is 1.75 cm, and the cross - sectional area of each electrode is 4cm^(2) . If the cell is filled wich 0.5(M) solution of an electrolyte, then the resistance of the cell becomes 25 ohm. Calculate the specific conductance of the solution.

a conductivity cell, the distance between two electrodes is 0.62 cm and the area of cross section of the electrode is 1.15 cm^2 . Find the cell constant of the cell.