1 g of ice at `0^@C` is mixed with 1 g of steam at `100^@C`. After thermal equilibrium is achieved, the temperature of the mixture is

60 g of ice at 0^(@)C is mixed with 60 g of steam at 100^(@)C . At thermal equilibrium, the mixture contains

60 g of ice at 0^@C is mixed with 60 g of steam at 100^@C . At thermal equilibrium, the mixture contains (Latent heat of steam and ice are 540 g^-1 and 80 cal g^-1 respectively, specific heat of water = 1cal g^-1^@C^-1 )

1g of ice at 0^@ C is mixed 1 g of steam at 100^@ C . The mass of water formed is

1 gram of ice is mixed with 1 gram of steam. At thermal equilibrium, the temperature of the mixture is

1 gram of ice is mixed with 1 gram of steam. At thermal equilibrium, the temperature of the mixture is

1 g of ice is mixed with 1 g of steam. At thermal equilibrium, the temperature of the mixture is¬