If n is a positive integer then the probability that `3^(n)` has 3 at unit place is

If x = 33^(n) , where n is a positive integral value, then what is the probability that x will have 3 at unit place?

If the four positive integers are selected randomly from the set of positive integers, then the probability that the number 1,3, 7 and 9 are in the unit place in the product of 4 - digit, so selected is

If n is a positive integer, then what is the digit in the unit place of 3^(2n+1)+2^(2n+1) ?

If n is a positive integer, then n^(3)+2n is divisible

If n be a positive integer, then the digit in the unit's place of 3^(2n-1)+2^(2n-1) is -

Let x = 33^n . The index n is given a positive integral value at random. The probability that the value of x will have 3 in the units place is

Let x=33^(n). The index n is given a positive integral value at random.The probability that the value of x will have 3 in the units place is

Let x = 33^n . The index n is given a positive integral value at random. The probability that the value of x will have 3 in the units place is

Let x = 33^n . The index n is given a positive integral value at random. The probability that the value of x will have 3 in the units place is