Escape velocity on a planet is e v . If radius of the planet remains same and mass becomes 4 times, the escape velocity becomes

Escape velocity on a planet is v_e , if the radius of the planet remains same and mass becomes four times, the escape velocity becomes

The escape velocity on a planet is v. If the radius of the planet contracts to (1/4)^(th) the present value without any change in its mass, then the escape velocity becomes

the escape velocity on a planet is v. if the radius of the planet contracts to 1/4 of the present value without any change in its mass, the escape velocity will be

The escape velocity of the earth is 11.2 km/s. For a planet whose mass and radius are twice those of the earth, the escape velocity will be

Escape velocity from a planet is v_(e) . If its mass is increased to 16 times and its radius is increased to 4 times, then the new escape velocity would be

Escape velocity from a planet is v_(e) . If its mass is increased to 16 times and its radius is increased to 4 times, then the new escape velocity would be

What is the value of escape velocity on a planet whose mass is 4 times and radius is half of earth? For earth escape velocity = 11.2 km s^-1 ?

The mass of a planet is six times that of the earth. The radius of the planet is twice that of the earth. It's the escape velocity from the earth is v , then the escape velocity from the planet is:

The value of the escape velocity from the earth is v_e . If the radius of a planet is 4 times that of the earth and its density is 9 times the density of the earth, then the value of the escape velocity from that planet will be