A motor-cyclist goes round a circular race course ar 150 kmph. How far from the vertical must be lean inward to keep his balance if the track is 1.5 km long ?

A motore cyclist goes round a circular race course of diameter 320m at 144km//h How far from the verticle must he lean inwards to keep his balance ? Take g = 10ms^(-2) .

A motor cyclist goes round a circular race course of diameter 320 m at 144 km h^(-1) . How far from the vertical must he lean inwards to keep his balance? Take g = 10 ms^(-2) .

A motorcyclist goes round a circular race curve at 162 kmh^(-1) . To keep his balance he leans inward 40° from the vertical. What is the radius of the circular path ?

A motor cyclist going round on unbanked circular race course has to lean inwards, making an angle 21^(@) 49 ' with the vertical , in order to keep his balance. If the curve is 1 km long , then the speed of the cyclist will be, ( tan 21^(@) 49 =0.4003' g=9.8 m//s ^(2) )

A cyclist goes once round a circular track of diameter 105 metre in 5 minute . Calculate his speed.

A man with his hands in his pocket is standing in a bus , which is taking a turn in a horizontal curve of radius 50 m , with a speed of 7 m/s far from the vertical must he lean to keep his balance ?

A cyclist is moving in a circular track of radius 80 m,, with a velocity of 36 km/ hour . In order to keep his balance , he has to lean inwards from the velocity through an angle theta if g= 10 m//s^(2) , then theta is given by

A cyclist goes round a circular track of radius 20sqrt3 m at a speed of 24sqrt3 ms^(-1) . What is the inclination to the vertical ?

A cyclist moves around a circular path of radius 39.2sqrt(3) metre with a speed of 19.6ms^(-1) '. He must lean inwards at an angle theta with the vertical such that tantheta is

A cyclist moves around a circular path of radius 39.2sqrt(3) metre with a speed of 19.6ms^(-1) '. He must lean inwards at an angle theta with the vertical such that tantheta is