Find a formula for maximum height attained by object.

Assume that an object is launched upward at 980m/seclis position would be given by s=-4.9t^2+980. Find the maximum height attained by the object

What do you mean by maximum height attained by a projectile ?

A body is projected from ground with velocity u making an angle theta with horizontal. Horizontal range of body is four time to maximum height attained by body. Find out (i) angle of projection (ii) Range and maximum height in terms of u (iii) ratio of kinetic energy to potential energy of body at maximum height

A body is projected from ground with velocity u making an angle theta with horizontal. Horizontal range of body is four time to maximum height attained by body. Find out (i) angle of projection (ii) Range and maximum height in terms of u (iii) ratio of kinetic energy to potential energy of body at maximum height

A body is projected from ground with velocity u making an angle theta with horizontal. Horizontal range of body is four time to maximum height attained by body. Find out (i) angle of projection (ii) Range and maximum height in terms of u (iii) ratio of kinetic energy to potential energy of body at maximum height

At which angle the maximum height attained by aprojectile is maximum ?

Find the maximum height attained by a body projected with a speed v=v_(e)//2 . Where v_(e )= escape velocity of any object at earth's surface.