Home
Class 11
PHYSICS
A force F = (5 hati + hatj) newtons is ...

A force `F = (5 hati + hatj)` newtons is is applied over a partical which displaced it from its origin to the point `r = (2 hati - hatj)` metres . The work done on the partical is.

Promotional Banner

Similar Questions

Explore conceptually related problems

A force vecF=(5hati+3hatj) Newton is applied over a particle which displaces it from its origin to the point vecr=(2hati-1hatj) metres. The work done on the particle is

A force vecF=(5hati+3hatj+2hatk)N is applied over a particle which displaces it from its origin to the point vecr=(2hati-hatj) m. The work done on the particle in joules is :

A force vecF=(5hati+3hatj)N is applied over a particle which displaces it from its original position to the point vecs=S(2hati-1hatj)m . The work done on the particle is

A force vecF=(5hati+3hatj)N is applied over a particle which displaces it from its original position to the point vecs=S(2hati-1hatj)m . The work done on the particle is

A force vecF =(5hati+3hatj+2hatk)N acts on a particle , and the particle moves from the origin to a point vecr=(2hati-hatj) m. what will be the work done on the particle ?

A force vec(F) = 4 hati + hatj + 3hatk newton acts on a particle and displaces it through displacement vec(S) = 11 hati + 11 hatj +15 hatj metre. Calculate the work done by the force.