Two balls are dropped from different heights at different instants. Seconds ball is dropped 2 sec. after the first ball. If both balls reach the ground simultaneousl after 5 sec. of dropping the first ball. then the difference of initial heights of the two balls will be :- `(g=9.8m//s^(2))`

Two balls are dropped to the ground from different heights.The second ball is dropped 3s after the first ball and both strike the ground at the same time. If the first ball took 6s to reach the ground,then the difference in the respective heights from which the two balls were dropped? (g=10m/s^(2))

Two balls are dropped to the ground from different heights. One ball is dropped 2 s after the other but they both strike the ground at the same time. If the first ball takes 5 s to reach the ground, then the difference in initial heights is (Take "g = 10 m s"^(-2) )

A ball is dropped from the top of a tower of height 78.4 m Another ball is thrown down with a certain velocity 2 sec later. If both the balls reach the ground simultaneously, the velocity of the second ball is

A ball is dropped from the top of a tower of height 78.4 m Another ball is thrown down with a certain velocity 2 sec later. If both the balls reach the ground simultaneously, the velocity of the second ball is