The curve `y-e^(xy)+x=0` has a vertical tangent at the point :

The curve x+y-log_(e)(x+y)=2x+5 has a vertical tangent at the point (alpha, beta). then alpha+beta is equal to

Find the point on the curve y-e^(xy)+x=0 . At which we have vertical tangent.

Prove that the curve y=e^(|x|) cannot have a unique tangent line at the point x = 0. Find the angle between the one-sided tangents to the curve at the point x = 0.

Prove that the curve y=e^(|x|) cannot have a unique tangent line at the point x = 0. Find the angle between the one-sided tangents to the curve at the point x = 0.

The curve given by x+y=e^(xy) has a tangent parallel to the y-axis at the point

The curve given by x+y=e^(xy) has a tangent parallel to the y-axis at the point (0,1)(b)(1,0)(1,1) (d) none of these

The curve given by x+y=e^(x y) has a tangent parallel to the y-axis at the point (a) (0,1) (b) (1,0) (c) (1,1) (d) none of these

The curve given by x+y=e^(x y) has a tangent parallel to the y - axis at the point (0,1) (b) (1,0) (c) (1,1) (d) none of these

The curve given by x+y=e^(x y) has a tangent parallel to the y- axis at the point (a) (0,1) (b) (1,0) (c) (1,1) (d) none of these

The curve given by x+y=e^(x y) has a tangent parallel to the y-axis at the point (a) (0,1) (b) (1,0) (c) (1,1) (d) none of these