The efficiency of carnot heat engine is 25%. When the temperature of the source alone is raised by 100K, the efficiency becomes 50%. Find the temperature of the source and the sink.

The efficiency of a carnot engine is (1)/(6) . If the temperature of the sink is reduced by 62 K, the efficiency becomes (1)/(3) . The temperature of the source and the sink in the first case are respectively.

The efficiency of a cannot's engine is 20%. When the temperature of the source is increased by 25^(@)C, then its efficiency is found to increase to 25%. Calculate the temperature of source and sink.

The efficiency of a Carnot engine is 1/2. If the sink temperature is reduced by 100^@ C , then engine efficiency becomes 2/3. Find the source temperature and sink temperature.

The efficiency of Carnot's enegine is 50% . The temperature of its sink is 7^(@)C . To increase its efficiency to 70% . What is the increase in temperature of the source?

The efficiency of Carnot's enegine is 50% . The temperature of its sink is 7^(@)C . To increase its efficiency to 70% . What is the increase in temperature of the source?

In a Carnot engine the temperature of source is 1000 K and the efficiency of engine is 70%. What is the temperature of the sink ?

The efficiency of carnot's heat engine is 0.5 when the temperature of the source is T_(1) and that of sink is T_(2) .The efficiency of another carnot's heat engine is also 0.5.the temperature of source and sink of the second engine are respecitvely

The efficiency of carnot's heat engine is 0.5 when the temperature of the source is T_(1) and that of sink is T_(2) .The efficiency of another crot's heat engine is also 0.5.the temperature of source and sink of the second engine are respecitvely