The value(s) of mass m for which the 100kg block does not move upward

The minimum value of mass m for which the 100 kg block can remain in static equilibrium is

The minimum value of mass m for which the 100 kg block can remain in static equilibrium is

A block of mass m collides with another block of mass 3m completely inelastically as shown in figure. What is the maximum value of v ( in m//s) for which the block B does not move. Assume that initially spring is in natural length and blocks A and B are at rest. (K//m=100 S.I. unit )

A block of mass m collides with another block of mass 3m completely inelastically as shown in figure. What is the maximum value of v ( in m//s) for which the block B does not move. Assume that initially spring is in natural length and blocks A and B are at rest. (K//m=100 S.I. unit )

Mass of upper block and lower block kept over the table is 2 kg and 1 kg respectively and coefficient of friction between the blocks is 0.1. Table surface is smooth. The maximum mass M for which all the three blocks move with same acceleration is (g = 10 m/s2) -

In the arrangement shown in the figure, block A of mass 8 kg rests on a horizontal table having coefficient of friction mu = 0.5 . Block B has a mass of 6 kg and rests on a smooth incline having inclination angle theta = sin^(-1) ((2)/(5)) . All pulleys and strings are mass less . Mass of block C is M . [g = 10 m//s^(2)] (a) Find value of M for which block B does not accelerate (b) Find maximum value of M for which A does not accelerate.

Two blocks A and B are connected by a string as shown as shown in the figure . Friction coefficient of the inclined plane is 0.5 . The mass of the block A is 5 kg. If minimum and maximum values of mass of the block B for which the block A remains in equilibrium are m_(1) and m_(2) then find the value of (m_(2) - m_(1)) [in kg]

The mass of a lift if 600kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is :

The mass of a lift if 600kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is :

The mass of a lift is 600 kg and it is moving upwards with a uniform acceleration of 2m//s^(2) . Then the tension in the cable of the lift is-