The equation of the tangent to the curve `y= be^(-(x)/(a))` at the point where it crosses the y-axis is-

The equation to the tangent to the curve y = be ^(-x/a) at the point where it crosses the y-axis is

The equation of the tangent to the curve y=b e^(-x//a) at the point where it crosses the y-axis is x/a-y/b=1 (b) a x+b y=1 a x-b y=1 (d) x/a+y/b=1

The equation of the tangent to the curve y=b e^(-x//a) at the point where it crosses the y-axis is a)x/a-y/b=1 (b) a x+b y=1 c)a x-b y=1 (d) x/a+y/b=1

The equation of the tangent to the curve y=b e^(-x//a) at the point where it crosses the y-axis is (a)x/a-y/b=1 (b) a x+b y=1 (c)a x-b y=1 (d) x/a+y/b=1

The equation of the tangent to the curve y=b e^(-x//a) at the point where it crosses the y-axis is (a)x/a-y/b=1 (b) a x+b y=1 (c)a x-b y=1 (d) x/a+y/b=1

The equation of the tangent to the curve y=be^(-(t)/(a)) at a point,where x=0 is

The equation of tangent to the curve y=be^(-x//a) at the point where it crosses Y-axis is

The equation to the tangent to the curve y=be^(x//a) at the point where x=0 is