A piece of lead falls from a height of 100m on a fixed non-conducting slab which brings it to rest. If the specific heat of lead is 30.6 cal/kg `.^(@)C`, the increase in temperature of the slab immediately after collision is

A piece of aluminium falls from a height of 200m on a fixed non conducting slab which brings it to rest. If the specific heat of aluminium is 210 Cal/kg. the increase in temperature of the slab immediately after collision (assume that there is no loss of heat)

A piece of aluminium falls from a height of 200 m on a fixed non conductig slab which brings it to rest. If the specific heat of aluminium is 210 Cal//kg^(@)C . The increase in temperature of the slab immediately after collision (assume that there is no loss of heat) is

A piece of lead falls from a height of 100 m on a fixed non - conducting slab which brings it to rest . The temperature of the piece immediately after collision increase by ( specific heat of lead is 30.6 cal kg^(-10) C^(-1) and g= 9.8ms^(-2) )

A piece of lead is dropped to the ground from a height of 200 m. What will be the increase in its temperature? Specific heat of lead = 0.03 cal cdot g^(-1) cdot^(@)C^(-1), J = 4.2 xx 10^(7) erg cdot cal^(-1)

A brass sphere of mass 0.2kg falls freely from a height of 20m and bounces to a height of 8m from the ground. If the dissipated energy in this process is absorbed by the sphere the eise in its temperature is (specific heat of brass =360 J kg^(-1)K^(-1) , g=10ms^(-2) )

A 100-g block of lead is heated from 20^@C to 50^@C . Calculate the amount of heat transferred to the block (specific heat of lead = 127 J.kg^-1.K^-1 ).

A body of mass 5 kg falls from a height of 20 metres on the ground and it rebounds to a height of 0.2 m. If the loss in potential energy is used up by the body, then what will be the temperature rise? ("specific heat of material = 0.09 cal gm"^(–1@)"C"^(–1))

A steel ball of mass 0.1 kg falls freely from a height of 10 m and bounces to a height of 5.4 m from the ground. If the dissipated energy in this process is absorbed by the ball, the rise in its temperature is (specific heat of steel =460 K//kg^(@)//C,g=10 m//s^(2) )

A steel ball of mass 0.1 kg falls freely from a height of 10 m and bounces to a height of 5.4 m from the ground. If the dissipated energy in this process is absorbed by the ball, the rise in its temperature is (specific heat of steel =460 K//kg^(@)//C,g=10 m//s^(2) )

A lead ball at 25^@ C is dropped from a height of 2 km. It is heated due to air resistance and it is assumed that all of its kinetic energy is used in increasing the temperature of ball. Find the final temperature of the ball.