A body of mass 2kg travels according to the law x(t) = `pt + qt^(2) + rt^(3)` where , q = `4 ms^(-2)` , p = `3 ms^(-1)` and `r = 5 ms^(-3)`. The force acting on the body at t = 2s is

A body of mass 2kg travels according to the law x(t) = pt + qt^(2) + rt^(3) where , q = 4 ms^(-1) , p = 3 ms^(-1) and r = 5 ms^(-1) . The force acting on the body at t = 2s is

A body of mass 2 kg travels according to the law x (t) = pt + qt^(2) + rt^(3) where, q = 4m s^(-2) , p - 3m s^(-1) and r = 5m s^(-3) . The force acting on the body at t = 2s is

A body of mass 2kg travels according to the law x (t) = pt + qt^(2) + rt^(3) where p = 3ms^(-1),q = 4 ms^(-2) and r = 5ms^(-3) . Find the force acting on the body at t=2 sec.

A body of mass 2kg travels according to the law x (t) = pt + qt^(2) + rt^(3) where p = 3ms^(-1),q = 4 ms^(-2) and r = 5ms^(-3) .

A body of mass 2 kg travels according to the law x (t) = pt + qt^2 + rt^3 where p = 3 ms^-1 q = 4 ms^-2 and r = 5 ms^-3 . the force acting on the body at t = 2 seconds is

A body of mass 2 kg is moving according to the equation for displacement at seconds as x(t) = pt^(2) + rt^(3). If p = 3 ms^(-1) , q = 4 ms^(-1) and r = 5 ms^(-1) the force acting after 2 sec is :

A body of mass 5kg moves according to the relation x=t^(2)+2t^(3) .The power used by the body at t=2s is?

A body of mass 1kg is moving according to the law x(t)=(5t+4t^(2)+6t^(3))m . The force acting on the body at time t=2s is

A body of mass 10 kg moves according to the relation x = t^(2) + 2t^(3) . The work done by the force in the first 2s is.