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A point sound source is situated in a me...

A point sound source is situated in a medium of bulk modulus `1.6times10^(5)N//m^(2)` . The equation for the wave emitted from it is given by `y=a sin(7.5 pi x-3000 pi t)` .Then velocity wave is v and the displacement amplitude of the waves received by the observer standing at a distance 5m from the source is A .The density of medium is `rho` .The maximum pressure amplitude tolerable to the observer's ear is `(30 pi )Pa`

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A point sound source is situated in a medium of bulk modulus 1.6times10^(5)N/m^(2) . The equation for the wave emitted from it is given by (y=a sin(7.5 pi x-3000 pi t)) . Then velocity wave is v and the displacement amplitude of the waves received by the observer standing at a distance 5m from the source is A.The density of medium is rho .The maximum pressure amplitude tolerable to the observer's ear is 30Pa then 1) qquad rho=1.5kg/m^(3) 2) v=400m/s 3)A=10^(-4) /4π m 4) qquad rho=2.5kg/m^(3)

A point sound source is situated in a medium of bulk modulus 1.6times10^(5)N/m^(2). The equation for the wave emitted from it is given by y=a sin(7.5π x-3000πt) .Then velocity wave is v and the displacement amplitude of the waves received by the observer standing at a distance 5m from the source is A.The density of medium is rho . The maximum pressure amplitude tolerable to the observer's ear is 30Pa then qquad rho=1.5kg/m^(3) qquad v=400m/s A =(10^(-4))/(4 pi)m

A point sound source is situated in a medium of dulk modulus 1.6 xx 10^(5) N//m^(2) . An observer standing at a distance 10 m from the source writes down the equeation for the wave as y = A sin (15 pi x - 6000 pi t) . Here y and x are in meter and t is in second. The maximum pressure ampulitude received to the observer's ear is (24 pi) pa, then find. (a) the density of the medium, (b) the displacement ampulitude A of the wave recived by the observer and (c ) the power of the sound source.

A point sound source is situated in a medium of dulk modulus 1.6 xx 10^(5) N//m^(2) . An observer standing at a distance 10 m from the source writes down the equeation for the wave as y = A sin (15 pi x - 6000 pi t) . Here y and x are in meter and t is in second. The maximum pressure ampulitude received to the observer's ear is (24 pi) pa, then find. (a) the density of the medium, (b) the displacement ampulitude A of the wave recived by the observer and (c ) the power of the sound source.

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