IF the normal to the parabola `y^2=4ax` at point `t_1` cuts the parabola again at point `t_2`, prove that `t_2^2ge8`

If the normal to the parabola y^2=4a x at point t_1 cuts the parabola again at point t_2 , then prove that (t_2)^2geq8.

If the normal to the parabola y^2=4a x at point t_1 cuts the parabola again at point t_2 , then prove that t_2^2 geq8.

If the normal to the parabola y^2=4a x at point t_1 cuts the parabola again at point t_2 , then prove that t_2 2geq8.

If the normal to the parabola y^2=4a x at point t_1 cuts the parabola again at point t_2 , then prove that (t_2)^2geq8.

If the normal to the parabola y^2=4a x at point t_1 cuts the parabola again at point t_2 , then prove that t2 2geq8.

If the normal to the parabola y^(2)=4ax at point t_(1) cuts the parabola again at point t_(2) then prove that t_(2)^(2)>=8

If the normal to the parabola y^(2)=4ax at point t_(1) cuts the parabola again at point t_(2) .Then the minimum value of t_(2)^(2) is

The normal to the parabola y^(2)=8ax at the point (2, 4) meets the parabola again at the point

The normal to the parabola y^(2)=8ax at the point (2, 4) meets the parabola again at the point