Two particles have time periods T and 5T/4. They start SHM at the same time from the mean postion. After how many oscillations of the particle having smaller time period, they will be again in the same phase ?

Two pendulums have time periods T and 5T//4 . They start SHM at the same time from the mean position After how many oscillations of the smaller pendulum they will be again in the same phase:

Two pandulums have time period T and (5T)/(4) . They S.H.M. at the same time from after the bigger pendulum has camplates one oscillation ?

Two pendulums have time period T and 5T/4. They starts SHM at the same time from the mean position. What will be the phase difference between them after the bigger pendulum completed one oscillation ?

Two pendulums have period T and (5T /4) s. They start S.H.M. at the same time from the mean position , the phase difference between them after the bigger pendulum has completed one oscillation is

Two pendulums having time period T and (5T)/(4) . They start S.H.M. at the same time from mean position. what will be the phase difference between them after the bigger pendulum has completes one oscillation ?

Two simple pendulums have time period T and 5T//4 . They start vibrating at the same instant from the mean position in the same phase. The phase difference (in rad) between them when the smaller pendulum completes one oscillation will be

Two simple pendulums have time periods T and 5T//4 . They start vibrating at the same instant from the mean position in the same phase. The phase difference between them when the pendulum with higher time period complets one oscillation is

The periodic times of two particles P and Q executing S.H.M. s are in the ration of 1 : 5. Both start moving from the mean position at the same ins"tan"t. After how many osicllations of P, the two particles will be again in phase at the mean position ?