A simple harmonic motion is represented by : `y = 5(sin 3pi t + sqrt(3) cos 3pi t)cm` The amplitude and time period of the motion are :

A simple harmonic motion is represented by : y=5(sin3pit+sqrt(3)cos3pit)cm The amplitude and time period of the motion by :

A simple harmonic motion is represented by : y=59sin3pit+sqrt(3)cos3pit)cm The amplitude and time period of the motion by :

A simple wave motion represented by y=5(sin 4pi t+sqrt3 cos 4pit) . Its amplitude is

A simple harmonic motion is given by y = 5(sin3pit + sqrt(3) cos3pit) . What is the amplitude of motion if y is in m ?

A SHM motion is represented by y=3sin2 pi t+4sin(2 pi t+(pi)/(6))+4sin(2 pi t+(5 pi)/(6))cm. The amplitude and time period of motion are ?

A simple harmonic motion is represented by the equation, y = 5 sin pi(t+4) . Then the values of amplitude A and initial phase prop are respectively.

A simple harmonic motion is represented by the equation, y = 5 sin pi(t+4) . Then the values of amplitude A and initial phase prop are respectively.

A simple harmonic motion is represented by y = 8 sin 10 pi t + 6 cos 10 pit , where is in cm and t is in sec. Calculate the amplitude time period and intial phase.