A body of mass `5kg` is thrown up vertically with a kinetic energy of `1000J`. If acceleration due to gravity is `10ms^(-2)`, find the height at which the kinetic energy becomes half of the original value.

A body of mass 2 kg is thrown up vertically with kinetic energy of 490 J . If g = 9.8m//s^(2) , the height at which the kinetic energy of the body becomes half of the original value, is

A body of mass 2 kg is thrown up vertically with kinetic energy of 490 J . If g = 9.8m//s^(2) , the height at which the kinetic energy of the body becomes half of the original value, is

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity =9.8ms^(-2) )

A body of mass 5 kg is thrown vertically up with a kinetic energy of 490 J. What will be height at which the kinetic energy of the body becomes half of the original value ? (Acceleration due to gravity =9.8ms^(-2) )

A body of mass 2 kg is thrown vertically upwards with K.E of 245 J. The acceleration due to gravity is 9.8 ms^(-2) . The K.E. Of the body will become half at the height of