The equation of the line through `(3, 4)` which cuts from the first quadrant a triangle of minimum area

A straight line through the point (3,4) in the first quadrant meets the axes at A and B . The minimum area of the triangle OAB is

Through the point (4,1) and making with the axes in the first quadrant a triangle whose area is 8.

The joint equation of lines passing through the origin and trisecting the first quadrant is

The joint equation of lines passing through the origin and trisecting the first quadrant is

The joint equation of lines passing through the origin and trisecting the first quadrant is

The joint equation of lines passing through the origin and trisecting the first quadrant is

A line through the point (-a,0) cuts from the second quadrant a triangular region with area T . The equation for the line is

A line through the point (-a,0) cuts from the second quadrant a triangular region with area T . The equation for the line is

The equation of a line parallel to 2x-3y=4 which makes with the axes a triangle of area 12 units,is-

The equation to the pair of lines through the origin and forming an equilateral triangle with the line 4x – 3y + 1 = 0 is