If `acostheta-bsintheta=c ,`then find the value of `asintheta+bcostheta`

If acostheta-bsintheta=c , then prove that: asintheta+bcostheta=+-sqrt(a^(2)+b^(2)-c^(2))

If acostheta-bsintheta=c , then prove that: asintheta+bcostheta=+-sqrt(a^(2)+b^(2)-c^(2))

If acostheta+bsintheta=c , then prove that: asintheta-bcostheta=+-sqrt(a^(2)+b^(2)-c^(2))

Find the greatest and least value of asintheta+bcostheta

If tantheta =a/b , find the value of (bcostheta-asintheta)/(b cos theta+a sin theta) .

If x=acostheta , y=bsintheta then eliminate theta .

If acostheta-bsintheta=c , then asintheta+bcostheta= (a) +-sqrt(a^2+b^2+c^2) (b) +-sqrt(a^2+b^2-c^2) (c) +-sqrt(c^2-a^2-b^2) (d) None of these

If tan theta=a/b ,then which of the following is the value of (asin theta+bcostheta)/(asintheta-bcostheta)?

If x=acostheta and y=bsintheta then the value of b^2x^2+a^2y^2 is

If btantheta=a , the value of (asintheta-bcostheta)/(asintheta+bcostheta) (a) (a-b)/(a^2+b^2) (b) (a+b)/(a^2+b^2) (c) (a^2+b^2)/(a^2-b^2) (d) (a^2-b^2)/(a^2+b^2)