A simple pendulum of length `4.9m` is immersed in a liquid of density `rho =0.4 kg//m^(3)`. Then the time period of pendulum is (density of bob `=0.8 kg//m^(3))`

The time period of a simple pendulum of length 9.8 m is

The time period of a simple pendulum of length 9.8 m is

Compare the time periods of two pendulums of length 1 m and 9 m.

The time period of a sample pendulum is T. Now the bob is immersed in a liquid of density sigma . If density of material of bob is rho , what will be the time period of the pendulum.

The time period of a simple pendulum in air is T . Now the pendulum is submerged in a liquid of density (rho)/(16) where rho is density of the bob of the pendulum. The new time period of oscillation is.

The time period of a simple pendulum in air is T . Now the pendulum is submerged in a liquid of density (rho)/(16) where rho is density of the bob of the pendulum. The new time period of oscillation is.

If the terminal speed of a sphere of gold (density = 9.5 kg m^(-3)) is 0.2 m/s in a viscous liquid (density = 1.5 kg m^(-3) ) the terminal speed of a sphere of silver (density = 10.5 kg m^(-3)) of the same size in the same liquid.

A simple pendulum with a metallic bob has a time preiod 10 s. The bob is now immersed in a non-viscous liquide of density 1/3 that of metal. the time period of the same pendulum becomes