The differential equation for `x^(3)+y^(3)=4ax` is

The differential equation for y=Ae^(3x)+Be^(-3x) is

Form differential equation for y=ax^(x)

The differential equation for y^(2)=(x+A)^(3) is

The differential equation of x^2+y^2=2Ax is

Show that y=ax^(3)+bx^(2)+c is a solution of the differential equation (d^(3)y)/(dx^(3))=6a

Form differential equation for y=x+2ax^(2)

If y^(2) = 4ax where a is constant then the differential equation formed is :

Let y = y (x) be the solution of the differential equation ( x - x ^(3)) dy = ( y + y x^(2) - 3x^(4)) dx , x gt 2 . If y (3) = 3 then y (4) is equal to :

The solution of the differential equation (dy)/(dx)=(3x^(2)y^(4)+2xy)/(x^(2)-2x^(3)y^(3)) is