If the curve satisfy the equation `(e^x+1) y dy = (y+1) e^x dx`, passes through `(0,0)` and `(k, 1)` then `k ` is

If the curve satisfy the equation (e^(x)+1)ydy=(y+1)e^(x)dx, passes through (0,0) and (k,1) then k is

The equation of the curve satisfying the eqution (xy-x^(2)) (dy)/(dx) = y^(2) and passing through the point (-1,1) is

The equation of the curve satisfying the eqution (xy-x^(2)) (dy)/(dx) = y^(2) and passing through the point (-1,1) is

If the given curve satisfy the differential equation e^(y)dx=(xe^(y)+2y)dy=0 and also passes through (0,0) then the possible equation of curve can be:

The foci of the curve which satisfies the equation (1+y^(2))dx - xy dy = 0 and passes through the point (1, 0) are

The foci of the curve which satisfies the equation (1+y^(2))dx - xy dy = 0 and passes through the point (1, 0) are

The curve satisfying the equation (x^(2)-y^(2))dx+2xydy=0 and passing through the point (1,1) is

If the curve satisfies the differential equation x.(dy)/(dx)=x^(2)+y-2 and passes through (1, 1), then is also passes through the point