If `f: R-{7/5}->R-{3/5}` be defined as `f(x)=(3x+4)/(5x-7)` and `g: R-{3/5}->R-{7/5}` be defined as `g(x)=(7x+4)/(5x-3)` . Show that `gof=I_A` and `fog=I_B` , where `B=R-{3/5}` and `A=R-{7/5}` .

If f:R-{(7)/(5)}rarr R-{(3)/(5)} be defined as f(x)=(3x+4)/(5x-7) and g:R-{(3)/(5)}rarr R-{(7)/(5)} be defined as g(x)=(7x+4)/(5x-3). Show that gof=I_(A) and fog=I_(B), where B=R-{(3)/(5)} and A=R-{(7)/(5)}

Show that if f: R-{7/5}->R-{3/5} is defined by f(x)=(3x+4)/(5x-7) and g: R-{3/5}->R-{7/5} is define by g(x)=(7x+4)/(5x-3) , then fog=I_A and gof=I_B , where A=R-{3/5}, B=R-{7/5}; I_A(x)=x ,AAx in A , I_B(x)=x ,AAx in B are called ideal

If f:RR -{(7)/(5)} rarr RR-{(3)/(5)} be defined as f(x)=(3x+4)/(5x-7) and g:RR- {(3)/(5)} rarr RR -{(7)/(5)} be defined as g(x)=(7x+4)/(5x-3) .Then find f o g .

Show that if f: R - {7/5} rarr R - {3/5} is defined by f(x) = (3x+4)/(5x-7) and g: R - {3/5} rarr R - {7/5} is defined by g(x) = (7x +4)/(5x-3) , then fog =I_A and gof = I_(B) , where A = R - {3/5} , B = R - {7/5} , I_(A) (x) = x, AA x in A , I_(B) (x) = x, AA x in B are called identity functions on sets A and B , respectively .

Let f: R-{3/5}->R be defined by f(x)=(3x+2)/(5x-3) . Then

Show that if f : R - {7/5} to R - {3/5} is defined by f(x) = (3x + 4)/(5x - 7) and g : R - {3/5} to R - {7/5} is defined by g(x) = (7x + 4)/(5x - 3) , then fog = I_(A) and gof = I_(n) , where A = R - {3/5}, B = R - {7/5}, I_(A) (x) = x, AA x in A, I_(B) (x) = x, AA x in B are called identify function on sets A and B, respectively.

If f" R -{3/5} to R be defined by f(x)=(3x+2)/(5x-3) , then :

Show that if f : R - {(7)/(5)} rarr R- {(3)/(5)} is defined by f (x) = (3x+4)/(5x-7) andc g:R - {(3)/(5)} rarr R - {(7)/(5)} is defined by g(x) = (7x+4)/(5x-3) then fog = I_(A) and gof = I_(B) where A = R - {(3)/(5)} B=R - {(7)/(5)} , I_(A) (x) = x AA x in A and I_(B) (x) =x AA x in B are called identity functions on sets A and B respectively.

Let f:R-{(3)/(5)}rarr R be defined by f(x)=(3x+2)/(5x-3). Then

If f:RR -{(7)/(5)} rarr RR-{(3)/(5)} be defined as f(x)=(3x+4)/(5x-7) then find f(0) .