Home
Class 12
CHEMISTRY
For the change, C("diamond") to C("graph...

For the change, `C_("diamond") to C_("graphite"), DeltaH = -1.89 kJ`, if 6g of diamond and 6g of graphite are separately burnt to yield `CO_2`, the heat liberated in first case is

Promotional Banner

Similar Questions

Explore conceptually related problems

For the change, C_("diamond") rarr C_("graphite"), Delta H = -1.89 kJ , if 6 g of diamond and 6 g of graphite are separately burnt to yield CO_2 the heat liberated in first case is:

For the change, C_("diamond") rarr C_("graphite"), Delta H = -1.89 kJ , if 6 g of diamond and 6 g of graphite are separately burnt to yield CO_2 the heat liberated in first case is:

The enthalpy change for chemical reaction is denoted as DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. For the change, C_("diamond") rarr C_("graphite"), DeltaH =- 1.89 kJ , if 6g of diamond and 6g of graphite are seperately burnt to yield CO_(2) the heat liberated in first case is

The enthalpy change for chemical reaction is denoted as DeltaH^(Theta) and DeltaH^(Theta) = H_(P)^(Theta) - H_(R)^(Theta) . The relation between enthalpy and internal enegry is expressed by equation: DeltaH = DeltaU +DeltanRT where DeltaU = change in internal enegry Deltan = change in number of moles, R = gas constant. For the change, C_("diamond") rarr C_("graphite"), DeltaH =- 1.89 kJ , if 6g of diamond and 6g of graphite are seperately burnt to yield CO_(2) the heat liberated in first case is

For the change C (diamond) rarr C(graphite) , Delta H=-1.89 KJ, if 6 g of diamond and 6g of graphite are seperately burnt to yield CO_(2) the heat liberated in first case is :

For the allotropic change represented by the equation C (graphit) rarr C (diamond), Delta H = 1.9 kJ . If 6g of diamond and 6 g of graphite are separately burnt to yield CO_(2) , the enthalpy liberated in first case is

C("diamond")toC("Graphite") , DeltaH=-ve . Then shows that

For the transition C_("(diamond)") rarr C_("(graphite)"), DeltaH=-1.5 kJ . It follows that