At `300^@C` the pressure necessary to obtained 80% dissociation of `PCl_5` is numerically equal to

Prove that the pressure necessary to obtain 50% dissociation of PCl_(5) at 250^(@)C is numerically three times of K_(p) .

Prove that the pressure necessary to obtain 50% dissociation of PCl_(5) at 250^(@)C is numerically three times of K_(p) .

Prove that the pressure necessary to obtain 50% dissociation of PCl_(5) at 500 K is numerically three times the value of K_(p) .

The equilibrium pressure necessary to obtain 50% dissociation of PCl_5 at 250^@C is numerically________of K_p .

Total equilibrium pressure necessary to obtain 60% dissociation of PCl_5 is P at 500 K. The relation between equilibrium constant K_p and P is

Phosphorus pentachloride dissociates as follows in a closed reaction vessel. PCl_5(g) hArr PCl_3(g) +Cl_2(g) If total pressure at equilibrium of the reactions mixture is P and degree of dissociation of PCl_5 is x, the partial pressure of PCl_3 will be:

Phosphorus pentachloride dissociates as follows in a closed reaction vessel PCl_5 (g) hArr PCl_3 (g) + Cl_2( g) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl_5 is x, the partial pressure of PCl_3 will be.