Home
Class 11
MATHS
P is the point on the ellipse isx^2/16+y...

P is the point on the ellipse is`x^2/16+y^2/9=1 and Q` is the corresponding point on the auxiliary circle of the ellipse. If the line joining the center C to Q meets the normal at P with respect to the given ellipse at K, then find the value of CK.

Promotional Banner

Similar Questions

Explore conceptually related problems

P is a point on the ellipse x^2/(25)+y^2/(9) and Q is corresponding point of P on its auxiliary circle. Then the locus of point of intersection of normals at P" & "Q to the respective curves is

The auxiliary circle of the ellipse x^(2)/25 + y^(2)/16 = 1

P is a point on the ellipse E:x^2/a^2+y^2/b^2=1 and P' be the corresponding point on the auxiliary circle C: x^2+y^2=a^2 . The normal at P to E and at P' to C intersect on circle whose radius is

If pi+theta is the eccentric angle of a point on the ellipse 16x^(2)+25y^(2) = 400 then the corresponding point on the auxiliary circle is

P is any point on the auxililary circle of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and Q is its corresponding point on the ellipse. Find the locus of the point which divides PQ in the ratio of 1:2 .

P is any point on the auxililary circle of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1 and Q is its corresponding point on the ellipse. Find the locus of the point which divides PQ in the ratio of 1:2 .

If P is a point on the ellipse (x^(2))/(36)+(y^(2))/(9)=1 , S and S ’ are the foci of the ellipse then find SP + S^1P

Q is a point on the auxiliary circle of an ellipse. P is the corresponding point on ellipse. N is the foot of perpendicular from focus S, to the tangent of auxiliary circle at Q. Then