The time period of a simple pendulum on the surface of the earth is 4s. Its time period on the surface of the moon is

The time period of a simple pendulum at the centre of the earth is

The period of a simple pendulum on the surface of the earth is 2s. Find its period on the surface of this moon, if the acceleration due to gravity on the moon is one-sixth that on the earth ?

The acceleration due to gravity on the surface of the Moon is 1.7ms^(-2) . What is the time period of a simple pendulum on the surface of the Moon, if its time period on the surface of Earth is 3.5 s? (g on the surface of the Earth is 9.8ms^(-2) ).

The acceleration due to gravity on the surface of the moon is 1.7ms^(-2) . What is the time perioid of a simple pendulum on the surface of the moon, if its time period on the surface of earth is 3.5s ? Take g=9.8ms^(-2) on the surface of the earth.

The acceleration due to gravity on the surface of the moon is 1.7ms^(-2) . What is the time perioid of a simple pendulum on the surface of the moon, if its time period on the surface of earth is 3.5s ? Take g=9.8ms^(-2) on the surface of the earth.

The acceleration due to gravity on the surface of the moon is 1.7ms^(-2) . What is the time perioid of a simple pendulum on the surface of the moon, if its time period on the surface of earth is 3.5s ? Take g=9.8ms^(-2) on the surface of the earth.

The acceleration dula to gravity on the surface of moon is 1.7ms^(-2) . What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5s ?

The acceleration due to gravity on the surface of moon is 1.7 m s^(-2) . What is the time period of a simple pendulum on the surface of moon if its time period on the surface of earth is 3.5 s ? (g on the surface of earth is 9.8 m s^(-2) )