At particle is executing `SHM` with amplitude `A` and has maximum velocity `v_(0)`. Find its speed when it is located at distance of `(A)/(2)` from mean position.

A particle is executing S.H.M. with amplitude A and has maximum velocity v_(0) . Its speed at displacement (3A)/(4) will be

A particle is executing S.H.M. with amplitude A and has maximum velocity v_(0) . Its speed at displacement (3A)/(4) will be

If a particle executing S.H.M. with amplitude A and maximum velocity vo, then its speed at displacement A/2 is

A particle executes a S.H.M. of amplitude A and maximum velocity V_(m) then its speed at displacement A//2 is

A particle is executing S.H.M. with amplitude 'A' and maximum velocity V_(m) . The displacement at which its velocity is half of the maximum velocity is

For a particle in SHM the amplitude and maximum velocity are A and V respectively. Then its maximum acceleration is

A particle is executing SHM with amplitude A , time period T , maximum acceleration a_(0) and maximum velocity V_(0) and at time t , it has the displacement A//2 , acceleration a and velocity V then

The frequency of oscillation of a particle executing SHM with amplitude A and having velocity 'v' at the mean position is