The potential energy of a particle moving along x-axis is given by `U = 20 + 5 sin (4 pi x)`, where `U` is in `J` and `x` is in metre under the action of conservative force :

The potential energy of the moving particle along x-axis is given by U=20+5sin (4pix) where U is in joule and x is in metre under the action of conservative force.

The potential energy of a particle oscillating on x-axis is given as U = 20 + (x-2)^(2) where .U. is in joules and .x. is in metres. Its mean position is

The potential energy of a particle of mass 2 kg moving along the x-axis is given by U(x) = 4x^2 - 2x^3 ( where U is in joules and x is in meters). The kinetic energy of the particle is maximum at

athe potential energy of a particle of mass 2 kg moving along the x-axis is given by U(x) = 4x^2 - 2x^3 ( where U is in joules and x is in meters). The kinetic energy of the particle is maximum at

Potential energy of a particle along x-axis varies as U = - 30 + (X-2)^2 , where U is in joule and x is in meter. Hence the particle is in

The potential energt of a particle of mass 0.1 kg, moving along the x-axis, is given by U=5x(x-4)J , where x is in meter. It can be concluded that

The potential energt of a particle of mass 0.1 kg, moving along the x-axis, is given by U=5x(x-4)J , where x is in meter. It can be concluded that

The potential energt of a particle of mass 0.1 kg, moving along the x-axis, is given by U=5x(x-4)J , where x is in meter. It can be concluded that

The potential energt of a particle of mass 0.1 kg, moving along the x-axis, is given by U=5x(x-4)J , where x is in meter. It can be concluded that