The positon vector of the centroid of the triangle ABC is `2i+4j+2k`. If the position vector of the vector A is `2i+6j+4k., then the position vector of midpointof BC is (A) `2i+3j+k` (B) `2i+3jk` (C) `2i-3j-k` (D) `-2i-3j-k`

The position vector of the centroid of the Delta ABC is 2i + 4j + 2k . If the position vector of the vertex A is 2i + 6j + 4k, then the position vector of midpoint of BC is a)2i + 3j + k b)2i + 3j - k c)2i - 3j - k d) -2i - 3j - k

The position vector of the centroid of the triangle formed by the points i + j + k, i - j + k, -i + j + k is

If the position vectors of A, B are 2i - 9j - 4k, 6i - 3j + 8k then the unit vector in the direction of vec(A)B is

If the position vectors of A and B are 3i - 2i + k and 2i + 4j - 3k then the length of AB is

If A = i + 2j + 3k and B = 2i - j + 4k, then the position vectors of the points of trisection are

If the position vectors of A, B are 2i + 3j + k and 3i - j + 4k repectively then the position vector of the point which divides AB in the ratio 3 : 2 is

If the position vectors of the vertices of a triangle are 2i - j + k, i - 3j - 5k, 3i - 4j - 4k then it is

Find the area of the triangle, the position vectors of whose vertices are a=i-2j+3k, b=j-k" and "c=2i+j