With a certain cell, the balance point is obtained at 65 cm from the zero end of a potentiometer wire. With another cell, whose e.m.f. is less than that of the first by 0.1 V, the balance point is obtained at 60 cm. What is the e.m.f. of the first cell ?

With a certain cell, the balance point is obtained at 65 cm from the end of apotentiometer wire. With another cell whose emf differs from that of the first by 0.1V the balance point is obtained at 60cm. Find the emf of each cell.

With a certain cell the balance point is obtained at 0.60 m from one end of the potentiometer. With another cell whose emf differs from that of the first by 0,1 V, the balance point is obtained at 0.55 m. Then, the two emf are

With a certain cell the balance point is obtained at 70 cm from the zero and of the potentiometer wire. With another cell whose emf differs from the 60 cm mark .Calculate the emf of the two cells

The null point in a potentiometer with a cell of e.m.f. xi is obtained at a distance l on the wire. Then :

In an experiment to find the internal resistance of a cell by a potentiometer, a balance was obtained for 50 cm length of the potentiometer wire, with a cell of e.m.f. 2V. When the cell was shunted by a resistance of 2 Omega , the balancing length of the potentiometer wire was 40 cm. What was the internal resistance of the cell ?

For a cell of e.m.f. 2 V , a balance is obtained for 50 cm of the potentiometer wire. If the cell is shunted by a 2Omega resistor and the balance is obtained across 40 cm of the wire, then the internal resistance of the cell is