The displacement of a simple harmonic oscillator is given by x = 4 cos `(2pit+pi//4)m`. Then velocity of the oscillator at t = 2 s is

The displacement of a simple harmonic oscillator is, x = 5 sin (pit//3) m . Then its velocity at t = 1 s, is

The displacement of a simple harmonic oscillator is x = 5 sin (pi t /3) m . Then its velocity at t =1 s , is

The displacement equation of a simple harmonic oscillator is given by y=A sin omegat-Bcos omegat The amplitude of the oscillator will be

The displacement of a particle executing simple harmonic motion is given by y = 4 sin(2t + phi) . The period of oscillation is

The displacement of a simple harmonic oscillator is given by y= 0.40 sin (440t +0.61) . For this, what are the value of amplitude.

An instaneous displacement of a simple harmonic oscillator is x = A cos(omegat + pi/4) . It speed will be maximum at time