1.5 of `CdCI_3` was found to contain of 0.9 g of Cd. Calculate the atomic of Cd.

1.5276 g of CdCl_2 was found to contain 0.9367 g of Cd. Calculate atomic weight of Cd.

1.5g CdCl_(2) was formed to contain 0.9g Cd. Calculate the atmic weight of Cd.

1.5276 grams of CaCl_(2) , was found to contain 0.9367 gram of Cd. Calculate the atomic weight of Cd.

1.5g CdCl_(2) was formed to contain 0.9g Cd. Calculate MO, the atomic weight of Cd.

The EMF of the cell, Zn|Zn^(2+) (0.1 M) || Cd^(2+) (M_(1)) |Cd has been found to be 0.3305 V at 298 K . Calculate the value of M_(1) [E_((Zn^(2+) |Zn))^(@) = - 0.76 V , E_((Cd^(2+) |Cd))^(Theta) = -0.40 V]

From the figure, given below . calculate the length of CD

CD_(4) complex is found on