The decay constant of a radioactive isotope is `lambda`. If `A_1` and `A_2` are its activites at time `t_1` and `t_2` respectively, then the number of nuclei which have decayed the time `(t_1-t_2)`

The decay constant of radio isotope is lambda . If A_(1) and A_(2) are its activities at times t_(1) and t_(2) respectively, the number of nuclei which have decayed during the time (t_(1)-t_(2))

The decay constant of a radioactive sample is lamda. Its half -life is T_(1//2) and mean life is T.

The radioactivity of a sample is l_(1) at a time t_(1) and l_(2) time t_(2) . If the half-life of the sample is tau_(1//2) , then the number of nuclei that have disintegrated in the time t_(2)-t_(1) is proportional to

The radioactivity of a sample is A_1 at time t_1 and A_2 at time t_2 If the mean life of the specimen is T , the number of atoms that have disintegrated in the time interval of (t_2 - t_1) is :

Half-life of a radioactive substance is T. At time t_1 activity of a radioactive substance is R_1 and at time t_2 it is R_2 . Find the number of nuclei decayed in this interval of time.

Half-life of a radioactive substance is T. At time t_1 activity of a radioactive substance is R_1 and at time t_2 it is R_2 . Find the number of nuclei decayed in this interval of time.

The activity of a sample of a radioactive meterial is A_1 , at time t_1 , and A_2 at time t_2(t_2 gt t_1) . If its mean life T, then

The activity of a sample of a radioactive meterial is A_1 , at time t_1 , and A_2 at time t_2(t_2 gt t_1) . If its mean life T, then

Decay constant of two radioactive samples is lambda and 3lambda respectively. At t = 0 they have equal number of active nuclei. Calculate t , when will be the ratio of active nuclei becomes e : 1 .