Find the intercepts of tehplane `3x+4y-7z=84` on the axes. Also find the length of perpendicular from origin to this plane and direction cosines of this normal.

Find the intercepts of a plane 3x+4y=7z=84 on co-ordinate axes.

Find the normal form of the plane x+2y-2z+6=0 . Also find the length of perpendicular from origin to this plane and the d.c.'s of the normal.

Find the normal form of the plane x+2y-2z+6=0 . Also find the length of perpendicular from origin to this plane and the d.c.'s of the normal.

A plane cuts off intercepts 3,-4,6 on the coordinate axes. The length of perpendicular from the origin to this plane is

The length of the perpendicular from the origin to the plane 3x+4y+12z ne 52 is

Reduce the equation 2x-3y-6z=14 to the normal form and hence fine the length of perpendicular from the origin to the plane. Also, find the direction cosines of the normal to the plane.

Reduce the equation 2x-3y-6z=14 to the normal form and hence fine the length of perpendicular from the origin to the plane. Also, find the direction cosines of the normal to the plane.

Reduce the equation of the plane x-2y-2z=12 to normal form and hence find the length of the perpendicular for the origin to the plane. Also, find the direction cosines of the normal to the plane.

Reduce the equation of the plane x-2y-2z=12 to normal form and hence find the length of the perpendicular for the origin to the plane. Also, find the direction cosines of the normal to the plane.

Find the normal form of the plane 2x+3y-z = 5 . Also find the length of perpendicular from origin and d.c's of the normal to the plane.