The period of SHM of a particle is 12 s. The phase difference between the positions at t = 3 s and t = 4 s will be

Two particles are executing S.H.M. according to the equations x_1 = 6 sin (10 pi t+ pi/3) and x_2 = 6 sin (8 pi t + pi/4) .Then the phase difference between the first and second particle at t = 0.5 s will be

The phase of a particle in S.H.M. is pi//2 , then :

The displacement of two particles executing S.H.M are represented by y_(1) = a sin(wt + phi) and y_(2) = a cos w t . The phase difference between the velocities of these particles is

In S.H.M., the phase difference between the displacement and velocity of a particle, at any isntant is

What is phase difference between the displacement and acceleration of a particle executing S.H.M ?

The period of a particle in SHM is 8s . At t=0 it is at the mean position. The ratio of the distances traveled by it in the first and the second second is

Two particles are executing S.H.M. according to the equations x_(1)=6sin(10pit+pi//3)andx_(2)=5cos(8pit+pi//4) Then the phase difference between the first and second particle at t = 0.5 s will be