The resistance of a wire of length `l` and diameter `d` is `R`. The wire is stretched to double its length. The resistance of the wire will now be

The resistance of a wire R Omega . The wire is stretched to double its length keeping volume constant. Now, the resistance of the wire will become

The resistance of a wire R Omega . The wire is stretched to double its length keeping volume constant. Now, the resistance of the wire will become

The resistance of a wire is 2 Omega . The wire is stretched to doubel its length. Now the resistance of the wire will become

A wire is stretched to n times its length. Then the resistance now will be increase by

A wire is stretched to n times its length. Then the resistance now will be increase by

If a wire is stretched to double its length, find the new resistance if the original resistance be R.

The resistance of wire of length l and area of cross-section a is x ohm. If the wire is stretched to double its length, its resistance would become:

A 8 ohm resistance wire is stretched to double its length. Calculate the new resistance of the wire.

A given wire is stretched to double its length. How will its resistance change ?