A wire has a resistance of `6 Omega`. It is cut into two parts and both half values are connected in parallel. The new resistance is ....

A wire of resistance (1 Omega ) is divided into two halves and both halves are connected in parallel. Find the new resistance.

A wire has a resistance of 90 Omega and it is cut into three pieces having equal lengths. If these are now connected in parallel, find the resistance of the combination so formed.

A uniform wire of resistance 40SN is cut into four equal parts and they are connected in parallel. The effective resistance of the combination is

A uniform wire of resistance (50 Omega) is cut into 5 equal parts. These parts are now connected in parallel.the Equivalent resistance of the combination is

A uniform wire of resistance (50 Omega) is cut into 5 equal parts. These parts are now connected in parallel.the Equivalent resistance of the combination is

A uniform wire of resistance (50 Omega) is cut into 5 equal parts. These parts are now connected in parallel.the Equivalent resistance of the combination is