When radiation of wavelength `lamda` is incidenton a metallic surface, the stopping potential is 4.8V. If the same surface is illuminated with radiation of double the wavelength, the stopping potential becomes 1.6V. What is the threshold wavelength for the surface?

When radiation of the wavelength lamda is incident on a metallic surface ,the stopping potential is 4.8 V. If the same surface is illuminated with radiation of double the wavelength ,then the stopping potential becomes 1.6 V.Then the threshold wavelength for the surface is

When radiation of the wavelength lamda is incident on a metallic surface ,the stopping potential is 4.8 V. If the same surface is illuminated with radiation of double the wavelength ,then the stopping potential becomes 1.6 V.Then the threshold wavelength for the surface is

When radiation of wavelength lambda is incident on a metallic surface , the stopping potential is 4.8 "volts" . If the same surface is illuminated with radiation of double the wavelength , then the stopping potential becomes 1.6 "volts" . Then the threshold wavelength for the surface is

When radiation of wavelength lambda is used to illuminate a metallic surface , the stopping potential is V. When the same suface is illuminated with radiation of wavelength 3 lambda the stopping is V/4 . If the therehold wavelength for the metallic

When radiation of wavelength lambda is used to illuminate a metallic surface , the stopping potential is V. When the same suface is illuminated with radiation of wavelength 3 lambda the stopping is V/4 . If the therehold wavelength for the metallic