Number of electrons required to deposit one mole of `Mg^(2+)` ions is

The amount of electricity required to deposit one gram atom of Mg from its molten salt is

Assertion (A) : The charge on one mole of electrons is one Faraday. Reason (R ) : The quantity of current required to deposit one mole of Mg form Mg^(2+) electrolyte solution is two Faradays. The correct answer is

The number of moles of electrons required to deposite 36 g of Al from an aqueous solution of Al(NO_(3))_(3) , is (At. wt. of Al = 27)

What is the amount of electricity required to deposit one mole of calcium form molten of CaCl_(2) ?

Assertion : 1 Faraday of electricity deposits 1 g equivalent of Ag,Cu or Al. Reason : 1 mole of electrons are required to reduce 1 mole of Ag^(+) or 1/2 mole of Cu^(2+) or 1/3 mole of Al^(3+) ions.

The number of faradays required to reduce one mole of Cu^(2+) to metallic copper is

Calculate the number of electrons required to deposit 41.5 g of Al