`100 cm^(3)` of a given sample of `H_(2)O_(2)`, gives `1000cm^(3)` of `O_(2)` at S.T.P. The given sample is

100 cm^(3) of a sample of H_(2)O_(2) gives 1000 cm^(3) of O_(2) at STP. The given sample is

100cm^3 of a given sample of H_2O_2 gives 1000cm^3 of O_2 at S.T.P. The given sample is

6 volume sample of H_(2)O_(2)

If 10 cm^(3) solution of H_(2)O_(2) on decomposition gives 150 cm^(3) of O_(2) at STP, then volume strength of H_(2)O_(2) is

20mL of sample of H_(2)O_(2) gives 400mL of oxygen measured at NTP. The sample should be labelled as:

100 ml of a sample of H_(2)O_(2) by dissociation yielded 560 ml O_(2) at NTP. The molarity and volume strength of the sample of H_(2)O_(2) is respectively