A plane surface is inclined making an angle `beta` above the horizon. A bullet is fired with the point of projection at the bottom of the inclined plane with velocity u, then the maximum range is given by:

An inclined plane making an angle beta with horizontal. A projectile projected from the bottom of the plane with a speed u at angle alpha with horizontal, then its maximum range R_("max") is

The velocity of the rolling object on inclined plane at the bottom of inclined plane is

A projectile is fired with a velocity v at right angle to the slope inclined at an angle theta with the horizontal. The range of the projectile along the inclined plane is

A projectile is fired with a velocity v at right angle to the slope inclined at an angle theta with the horizontal. The range of the projectile along the inclined plane is

A bullet is fired with a velocity u making an angle of 60^(@) with the horizontal plane. The horizontal component of the velocity of the bullet when it reaches the maximum height is

A particle is projected from the inclined plane at angle 37^(@) with the inclined plane in upward direction with speed 10m//s . The angle of inclined plane with horizontal is 53^(@) . Then the maximum height attained by the particle from the inclined plane will be-

A particle is projected from the inclined plane at angle 37^(@) with the inclined plane in upward direction with speed 10m//s . The angle of inclined plane with horizontal is 53^(@) . Then the maximum height attained by the particle from the inclined plane will be-