Two particles `p` and `q` located at distances `r_p` and `r_q` respectively from the centre of a rotating disc such that `r_p gt r_q`.

Two particles P and Q located at distancer, andr, respectively from the centre of a rotating disc such that r_(P) > r_(Q)

Two particles P and Q are located at distance r_(p) and r_(Q) respectively form the centre of rotating disc such that r_(P)gtr_(Q) . The disc is rotating with constant angular acceleration. We can say

In Figure, P Q > P R. Q S\ a n d\ R S are the bisectors of /_ Q and /_R respectively. Prove that S Q > S R .

In a Delta ABC , if p,q,r are the distances from the orthocentre to the vertices A,B,C respectively, then a q r + b r p+ c p q =

If a,b,c are respectively the sums of p,q,r terms of an A.P., prove that a/p(q-r)+b/q(r-p)+c/r(p-q)=0

Sum of the first p, q and r terms of an A.P. are a, b and c, respectively. Prove that a/p(q-r)+b/q (r-p) +c/r (p-q)=0

If the pth , qth and rth terms of an A.P. be P, Q and R respectively then show that, p(Q-R) + q(R-P) + r(P-Q) = 0 .

Sum of the first p, q and r terms of an A.P are a, b and c, respectively.Prove that a/p(q-r)+b/q(r-p)+c/r(p-q)=0